0
What else can I help you with?
Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
What is the answer to 24x3-5x2-48x-8 divided by 8x plus 4?
If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
How do you do (5x2 8x)-(3x2-x)?
In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.
How do you factor 5x2 plus 20x?
5x2 + 20x = 5x (x + 4)
Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
What is the answer to 24x3-5x2-48x-8 divided by 8x plus 4?
If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
How do you do (5x2 8x)-(3x2-x)?
In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.
What are the factors of this quadratic trinomial 5x2-8x-4?
(5x+2) and (x-2)
How do you factor 5x2 plus 20x?
5x2 + 20x = 5x (x + 4)
What is 4x squared times x over 4 times 8x minus 32?
(4x2) (x/4)(8x - 32) =x3(8x - 32) = 8x3(x - 4)
How do you factor 12x2-8x-4?
12x2-8x
How do you factor -5x2 plus 9x-4?
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
How do you factor 5x2 - 4x?
x(5x - 4)
How do you factor 5x2 plus 20?
5x2 + 20 = 5*(x2 + 4) which cannot be factorised further.
What are the solutions of 5x2 plus 8x equals 7?
5x2 + 8x = 7 5x2 + 8x - 7 = 0 This cannot be factorised so the solutions need to be determined using the quadratic formula The solutions are {-8 ± sqrt[82 - 4*5*(-7)]}/(2*5) = {-8 ± sqrt[64 + 140]}/10 = {-8 ± sqrt[204]}/10 = -2.22829 and 0.62829 (to 5 dp)
