One acre = 4840 square yards, or (4840 x 9) square feet.
if you have the area. divide the area by the length to get the width. If you have the perimeter subtract the length twice and divide the number you have by two. If it is a square the width is the same as the length.
Multiply both the length and width by the samenumber to get a similar figure.It doesn't matter what the number is.
All solid figures have length, width and height and, conversely, if a figure has length, width and height then it is a solid figure.
The Atlanta Zoological Park covers 40 acres. I don't have the numbers for its length and width.
0.5 acres = 21,780 square feet.So you know that (length) times (width) must be 21,780 but there are noother constraints on what the dimensions must be. There are an infinite numberof possible length/width combinations.
A square with an area of 99 acres has a length and width of 2,077 feet.
if you have the area. divide the area by the length to get the width. If you have the perimeter subtract the length twice and divide the number you have by two. If it is a square the width is the same as the length.
A square with an area of 80 acres has a length and width of 1,867 feet. The diagonal length of the square is 2,640 feet.
Multiply both the length and width by the samenumber to get a similar figure.It doesn't matter what the number is.
depends on the length
All solid figures have length, width and height and, conversely, if a figure has length, width and height then it is a solid figure.
Answer: 12.397 acres.
One acre equals 43, 560 square feet. To calculate the area in acres, multiply the length by the width in feet, then divide by the above figure.
Convert that to square feet. As a reminder, an acre is 43,560 square feet. Then, choose any width you like; divide the number of square feet by that number to get the corresponding length (for a rectangular area).
A plane figure.
The Atlanta Zoological Park covers 40 acres. I don't have the numbers for its length and width.
0.5 acres = 21,780 square feet.So you know that (length) times (width) must be 21,780 but there are noother constraints on what the dimensions must be. There are an infinite numberof possible length/width combinations.