9E-05x
oxidation
2e - 12 = 7e + 8Add 12 to both sides: 2e = 7e + 20 subtract 7e from both sides: -5e = 20 divide both sides by -5: e = -4
MgCl2 aq plus Zn s is the oxidation half-reaction for Mg s plus ZnCl2 aq.
10 + 10 + 10 + 5 + 5 +1 = 41.
It can be simplified to: 4f+2e
Zn2+ + 2e- <--> Zno -0.7618 V
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
Simplified is 5e-2f.
2e-bc/a = 2 2e - bc / a = [2(20) - (3)(10)] / 5 = [40-30]/5 = 10/5
9E-05x
Mg equals Mg2+ plus 2e-
oxidation
-2.37 V (apex) Chace
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
2e - 12 = 7e + 8Add 12 to both sides: 2e = 7e + 20 subtract 7e from both sides: -5e = 20 divide both sides by -5: e = -4
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