49cm2
9x9=81 Each side would be 9; so 9x4=36 if it's a square.
The outer boundary of a body or figure.
12.25 square cm
The perimeter is 31.11 units.
Multiply one of the sides by 4.
49cm2
The perimeter would be 28 cm
9x9=81 Each side would be 9; so 9x4=36 if it's a square.
it is the area of a solid object times by the square root of the perimiter
The area of square is the square of one of its sides, which are all equal. To find the value of a side, take the square root of the area. In this case the square root of 49cm2 is 7cm. The perimeter is the sum of all four sides of the square, so the perimeter of a square with an area of 49cm2 is 7+7+7+7 = 28, or 4x7 = 28.
The outer boundary of a body or figure.
12.25 square cm
The area of square is the square of one of its sides, which are all equal. To find the value of a side, take the square root of the area. In this case the square root of 49cm2 is 7cm. The perimeter is the sum of all four sides of the square, so the perimeter of a square with an area of 49cm2 is 7+7+7+7 = 28, or 4x7 = 28.
base times height minus half of the perimiter base times height minus half of the perimiter
No, squares do not represent perimeters.
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