y=3x-5
3x5
95
5+5+5
The generalisation is that multiplication is Abelian (or commutative) for numbers.
3x5+4=19
3x5
95
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
5+5+5
The generalisation is that multiplication is Abelian (or commutative) for numbers.
3x5+4=19
2+3*5 = 2 + 15 = 17
Ah, what a happy little question! The inverse operation of multiplication is division, so to find the inverse of 3x5 equals 15, you would divide 15 by 5 to get 3. Remember, math is like painting a beautiful landscape - just follow the steps with a gentle touch and you'll create something wonderful.
Commutivity of multiplication or the commutative property of multiplication.
15/40 = (3x5)/(8x5) = 3/8
r = 3 s = 5 t = 6 rs = 3x5 = 15 rt = 3x6 = 18 st = 5x6 = 30
No, a 3x5 matrix cannot be multiplied by another 3x5 matrix. For matrix multiplication to be possible, the number of columns in the first matrix must equal the number of rows in the second matrix. Since a 3x5 matrix has 5 columns and the second 3x5 matrix has 3 rows, multiplication is not defined in this case.