3 x 3 x 3 = 27
27 squared is equal to (27^2). Since 27 can be expressed as (3^3), we have (27^2 = (3^3)^2). Using the power of a power rule, this simplifies to (3^{3 \times 2} = 3^6). Therefore, 27 squared as a power of 3 is (3^6).
square root of 9 is 3.
a(squared)+b(squared)=c(squared) The largest number is the c, and you can choose the a and b, since you need to find the a or the b. For example: You have the numbers 3, and 5 and you needed to find b. a(squared+b(squared)=c(squared) 3(squared)+b(squared)=5(squared) 9+b(squared)=25 -9 -9 b(squared)=16 Then take the square root b=4
27
27*y*8 can simplify to 3^3 * y * 2^3. Then, you take out all the squared pairs to get 6 sqrt(6y).
27 squared is equal to (27^2). Since 27 can be expressed as (3^3), we have (27^2 = (3^3)^2). Using the power of a power rule, this simplifies to (3^{3 \times 2} = 3^6). Therefore, 27 squared as a power of 3 is (3^6).
square root of 9 is 3.
a(squared)+b(squared)=c(squared) The largest number is the c, and you can choose the a and b, since you need to find the a or the b. For example: You have the numbers 3, and 5 and you needed to find b. a(squared+b(squared)=c(squared) 3(squared)+b(squared)=5(squared) 9+b(squared)=25 -9 -9 b(squared)=16 Then take the square root b=4
27
root 27 = root 9 x root 3 = 3 root 3. Dividing this by root 3 gives 3!
27*y*8 can simplify to 3^3 * y * 2^3. Then, you take out all the squared pairs to get 6 sqrt(6y).
the third root of 27 is 3
(3 root 7) squared = (3 root 7) (3 root 7) = (3x 3) ( sq root 7 x 7) = 9 x sq root 49 = 9 x 7 = 63
Well, honey, 2 squared is 4 and 3 cubed is 27, so when you multiply them together, you get 108. So, there you have it - 2 squared times 3 cubed equals 108. Math can be a piece of cake when you break it down!
Three
2.080084
The square root of 9 is the number you times by itself to get 9, so that's 3. Then to cube it you do 3 x 3 x 3 which is 27.