Pi R2
Area = pi R2
To find the diameter of a circle you multiply the radius by 2 or d=r2
Using the formula for the surface area of a sphere, which is SA = 4 (pi) r2, you can find the radius, and the diameter of the sphere is twice the radius. Example: If the surface of a sphere is 380 square cm 4 (pi) r2 = SA 4 (3.1416) r2 = 380 12.5664 r2 = 380 r2 = approx. 30.24 r = 5.5 and diameter D = 11 cm
S=4*pi*r2
Pi R2
The area of a circle is pi * r2 where r is the radius Solving for r, where A is the area: A = pi * r2 A/pi = r2 r = sqrt(A/pi)
yes press R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2, then press select to complete the entire game
The formula for the volume of a cylinder, which is h(pi)r2, is the area of the base (pi)r2 multiplied by the height (h). If you are given the diameter instead, remember that the diameter is twice the radius.So if we know that V = h(pi)r2, we can rearrange the formula in order to find the height.Divide the whole equation by (pi)r2. The result is: V ÷ (pi)r2 = h OR h = V ÷ (pi)r2.The formula h = V ÷ (pi)r2 means the height (h) is equal to the volume (V) divided by the area of the base (pi)r2.
pi r2
Area = pi R2
To find the diameter of a circle you multiply the radius by 2 or d=r2
Using the formula for the surface area of a sphere, which is SA = 4 (pi) r2, you can find the radius, and the diameter of the sphere is twice the radius. Example: If the surface of a sphere is 380 square cm 4 (pi) r2 = SA 4 (3.1416) r2 = 380 12.5664 r2 = 380 r2 = approx. 30.24 r = 5.5 and diameter D = 11 cm
for serial: r = r1 + r2; for paralel: r = 1/ (1/r1 + 1/r2);
The radius will be about 5.87 (units). The formula for the area is A = (pi) r2 where pi is about 3.1416 and r is the radius (squared) 108 = 3.1416 (r2) 34.38 = r2 r = about 5.87
(R1 * R2) / (R1 + R2) = 2 Parallel R1 + R2 = 9 Series Treating the two as simultaneous equations, and substituting for R1: ((9-R2) * R2) / (9 - R2 + R2) = 2 R2^2 - 9R2 + 18 = 0 Solving the quadratic, we get: R2 = 6 ohm R1 = 3 ohm Which you can check by substituting back into the original equations.
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