There are many ways to find the angle of a slope.
One easy practical way to see if a slope is 10 degrees is to have a 1 metre long (1000 mm) straight edge and put one end on the slope surface while holding it horizontal with a spirit level. The "free" end will be 176 mm (176.327 mm) off the surface if the slope is 10 degrees.
(Tan 100 = 176 / 1000 to nearest round figures).
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An example of an inclined plane is a ramp, slanted road, or a slide. An inclined plane is a surface that is at an angle against a horizontal surface.
The answer depends on which angles are unknown. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
For every 4.5 rise, the run is 100, hence tangent of the angle of inclination is (4.5/100) = 0.045. Now find out the angle whose tangent is 0.045 from a table or using a calculator. It turns out to be 2.576 degrees
To find the speed you would need to find the time taken to create the skid marks and then use the equations of motion. As the vehicle is skidding, the wheels are not turning so the braking force is the friction between the tyre and the road surface; this has to overcome the forward speed of the vehicle and the forward force of the weight of the vehicle along the road (as there is a downward slope). The forward force of the vehicle can be calculated by knowledge of the mass of the vehicle and the angle of the slope. The frictional force generated can be calculated from the coefficient of friction between the tyres and the road surface, and the mass of the vehicle. The road being wet will reduce the coefficient of friction of the road surface/tyre boundary compared to when the road surface is dry. It is easier, by experiment, to do a few test runs using a vehicle of similar mass under similar conditions to get how the vehicle is likely to have slowed down when it skidded, and extrapolate/interpolate to the given distance of 24.2 m.
Surely it must be the camber?