You do not have absolute deviation in isolation. Absolute deviation is usually defined around some measure of central tendency - usually the mean but it could be another measure.
The absolute deviation of an observation x, about a measure m is |x - m| which is the non-negative value of (x - m). That is,
|x - m| = x - m if x ≥ m
and m - x if x < m
None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0
Add all the absolute deviations together and divide by their number.
You calculate the mean.For each observation, you calculate its deviation from the mean.Convert the deviation to absolute deviation.Calculate the mean of these absolute deviations.
The answer depends on the purpose. The interquartile range and the median absolute deviation are both measures of spread. The IQR is quick and easy to find whereas the MAD is not.
The range and mean absolute deviation are: Range = 29 Mean absolute deviation = 8.8
None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0
Add all the absolute deviations together and divide by their number.
You calculate the mean.For each observation, you calculate its deviation from the mean.Convert the deviation to absolute deviation.Calculate the mean of these absolute deviations.
The mean absolute deviation of this problem is 6.
The mean absolute deviation is 28.5
The answer depends on the purpose. The interquartile range and the median absolute deviation are both measures of spread. The IQR is quick and easy to find whereas the MAD is not.
The range and mean absolute deviation are: Range = 29 Mean absolute deviation = 8.8
Absolute deviation from what?
To calculate the average deviation from the average value, you first find the average of the values. Then, subtract the average value from each individual value, take the absolute value of the result, and find the average of these absolute differences. This average is the average deviation from the average value.
I am pretty sure they are not.
Mean Absolute Deviation
If I have understood the question correctly, despite your challenging spelling, the standard deviation is the square root of the average of the squared deviations while the mean absolute deviation is the average of the deviation. One consequence of this difference is that a large deviation affects the standard deviation more than it affects the mean absolute deviation.