In general this question is unanswerable.
However, you can consider Newton's method to make very good estimates.
Equations can be very complex in that their curves have poles and zeros where you do not expect them. Consider Riemann's Zeta function Z(z) = Sum(1/n^z, n>0). It has complex zeros on the line z=1/2, but up to this date, the distribution of the zeros is not entirely known!
Yes, a cubic equation can have three imaginary solutions, but this occurs only when all the roots are complex. For a cubic equation with real coefficients, if it has one real root, the other two roots must be complex conjugates, resulting in one real and two imaginary solutions. However, if the cubic has no real roots, it can have three distinct complex roots, all of which would be imaginary.
A quadratic function can have up to two roots. Depending on the discriminant (the expression under the square root in the quadratic formula), it can have two distinct real roots, one repeated real root, or no real roots at all (in which case the roots are complex). Therefore, the total number of roots, considering both real and complex, is always two.
-1.1402 and 1.1402, approx.
Some common myths about polynomials include: All polynomials have real roots: This is false; polynomials can have complex roots as well. The degree of a polynomial dictates its shape: While the degree influences the general behavior, other factors like coefficients also play a significant role. Polynomials must have integer coefficients: Polynomials can have coefficients that are rational, real, or even complex numbers. A polynomial of degree n always has n roots: This is only true in the complex number system; in the real number system, some roots may be complex or repeated.
You can square any real number (complex ones too) so the domain is all real numbers.
( +0.063246 ) and ( -0.063246 ).These numbers are rounded.These are the only square roots of 0.004. There are no more real ones,and no imaginary or complex ones.
Yes, a cubic equation can have three imaginary solutions, but this occurs only when all the roots are complex. For a cubic equation with real coefficients, if it has one real root, the other two roots must be complex conjugates, resulting in one real and two imaginary solutions. However, if the cubic has no real roots, it can have three distinct complex roots, all of which would be imaginary.
A quadratic function can have up to two roots. Depending on the discriminant (the expression under the square root in the quadratic formula), it can have two distinct real roots, one repeated real root, or no real roots at all (in which case the roots are complex). Therefore, the total number of roots, considering both real and complex, is always two.
A cubic equation, which is typically in the form ( ax^3 + bx^2 + cx + d = 0 ), always has three roots in the complex number system, counting multiplicities. These roots could be all real, or one real root and two complex conjugate roots depending on the discriminant. Thus, while there are always three roots in total, their nature (real or complex) can vary.
.06 and .06
-1.1402 and 1.1402, approx.
The real fourth roots are -0.3 and 0.3
sqrt(0.0004) = +/- 0.02. Try calculating (+0.02)^2 and (-0.02)^2 by hand to convince yourself that both are real roots of 0.0004. ================
The square of a "normal" number is not negative. Consequently, within real numbers, the square root of a negative number cannot exist. However, they do exist within complex numbers (which include real numbers)and, if you do study the theory of complex numbers you wil find that all the familiar properties are true.
You can square any real number (complex ones too) so the domain is all real numbers.
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
In mathematics, a cube root of a number, denoted or x1/3, is a number a such that a3 = x. All real numbers (except zero) have exactly one real cube root and a pair ofcomplex conjugate roots, and all nonzero complex numbers have three distinct complex cube roots. For example, the real cube root of 8 is 2, because 23 = 8. All the cube roots of −27iareThe cube root operation is not associative or distributive with addition or subtraction.The cube root operation is associative with exponentiation and distributive with multiplication and division if considering only real numbers, but not always if considering complex numbers, for example:but