In general this question is unanswerable.
However, you can consider Newton's method to make very good estimates.
Equations can be very complex in that their curves have poles and zeros where you do not expect them. Consider Riemann's Zeta function Z(z) = Sum(1/n^z, n>0). It has complex zeros on the line z=1/2, but up to this date, the distribution of the zeros is not entirely known!
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-1.1402 and 1.1402, approx.
You can square any real number (complex ones too) so the domain is all real numbers.
No. Negative four is a real number. All real numbers are also complex numbers, so it is a complex number (but it's real, not nonreal)
-15 15
14i