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In general this question is unanswerable.
However, you can consider Newton's method to make very good estimates.
Equations can be very complex in that their curves have poles and zeros where you do not expect them. Consider Riemann's Zeta function Z(z) = Sum(1/n^z, n>0). It has complex zeros on the line z=1/2, but up to this date, the distribution of the zeros is not entirely known!
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Find all the real square roots of 1.3?
-1.1402 and 1.1402, approx.
How do you find out the domain of x squared?
You can square any real number (complex ones too) so the domain is all real numbers.
Is -4 a nonreal complex number?
No. Negative four is a real number. All real numbers are also complex numbers, so it is a complex number (but it's real, not nonreal)
What are all the real square roots of negative 196?
14i
All the real square roots of 400?
-15 15
Find all the real square roots of 0.004?
( +0.063246 ) and ( -0.063246 ).These numbers are rounded.These are the only square roots of 0.004. There are no more real ones,and no imaginary or complex ones.
Find all real square roots of 0.0036?
.06 and .06
Find all the real square roots of 1.3?
-1.1402 and 1.1402, approx.
What are all the real fourth roots of 0.0081?
The real fourth roots are -0.3 and 0.3
Find all the real square roots of 0.0004?
sqrt(0.0004) = +/- 0.02. Try calculating (+0.02)^2 and (-0.02)^2 by hand to convince yourself that both are real roots of 0.0004. ================
Why properties of square roots are true only for non negative numbers?
The square of a "normal" number is not negative. Consequently, within real numbers, the square root of a negative number cannot exist. However, they do exist within complex numbers (which include real numbers)and, if you do study the theory of complex numbers you wil find that all the familiar properties are true.
How do you find out the domain of x squared?
You can square any real number (complex ones too) so the domain is all real numbers.
How do you write cubed roots?
In mathematics, a cube root of a number, denoted or x1/3, is a number a such that a3 = x. All real numbers (except zero) have exactly one real cube root and a pair ofcomplex conjugate roots, and all nonzero complex numbers have three distinct complex cube roots. For example, the real cube root of 8 is 2, because 23 = 8. All the cube roots of −27iareThe cube root operation is not associative or distributive with addition or subtraction.The cube root operation is associative with exponentiation and distributive with multiplication and division if considering only real numbers, but not always if considering complex numbers, for example:but
How many real roots can a fourth degree polynomial have?
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
How do you find complex zeros on a graph?
It's actually quite hard to graph complex numbers - you would need a four-dimensional space to graph them adequately. I believe it's more convenient to find zeros analytically for such functions.
Is -4 a nonreal complex number?
No. Negative four is a real number. All real numbers are also complex numbers, so it is a complex number (but it's real, not nonreal)
What are all the real square roots of 0.0625?
0.0625 has a grand total of 2 square roots, and they're both real. They are +0.25 and -0.25
