If the shape in question is not a triangle, I don't know. If it is,
let a, b and c be the lengths of the three sides.
and let s = (a + b + c)/2
Then Area = sqrt[s*(s-a)*(s-b)*(s-c)]
The answer will depend on the nature of the polygon and what is known about it.For a triangle, for example, there are formulae if you know 3 sides; or 2 sides and an angle; or 1 side and 2 angles. In the second case you can find the area but not the perimeter.In the case of a quadrilateral, you will require much more information, and for polygons with more sides, even more.
first find the area of one face so 3times 3= 9 in. square then 9 in times all 6 sides =54 in. square
If you know the lengths of 2 sides and the included angle then use: Area of a triangle = 1/2*a*b*sinC
The surface are is 136 sq in. You have to find the area of each of the six sides. 2 sides will have dimensions of 8x3 (48 sq in) 2 sides will have dimensions of 8x4 (64 sq in) 2 sides will have dimensions of 3x4 (24 sq in) Finally add them all up.
In order to find the surface area we must first find the radius of the sphere:- Volume of the sphere = 4/3*pi*radius3 = 113.1 cubic inches Multiply both sides by 3: 4*pi*radius3 = 339.3 Divide both sides by 4*pi: radius3 = 27.0006361 Cube root both sides: radius = 3.000033559 Surface area of the sphere = 4*pi*3.0000235592 = 113.0991118 square inches
area = length by length. 3 x 3 = 9 units squared
9 meters squared
Use trigonometry
Find the area of one of the sides and then multiply it by 3 (3 sides to a triangular pyramid)Then work out the area of the base of the pyramid, and add it to the total area of all the sides.Area of a triangle = Base x Height / 2
Add together the areas of all 6 sides.
The answer will depend on the nature of the polygon and what is known about it.For a triangle, for example, there are formulae if you know 3 sides; or 2 sides and an angle; or 1 side and 2 angles. In the second case you can find the area but not the perimeter.In the case of a quadrilateral, you will require much more information, and for polygons with more sides, even more.
18*sqrt[3]
first find the area of one face so 3times 3= 9 in. square then 9 in times all 6 sides =54 in. square
If those are sides of a quadrilateral, you can't calculate the area - there is insufficient information. The same sides can be connected at different angles, resulting in different areas.
You cannot. The length of the sides of a quadrilateral do not provide sufficient information to find its area. In the same way the a square can be distorted into a thinner and thinner rhombus with a smaller and smaller area, so can any quadrilateral.
There is no area because rectangles do not have equal sides.
Divide the perimeter by 3 to find the length of each of its 3 equal sides Area = 0.5*side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find its height then area is: 0.5*base*height