If the shape in question is not a triangle, I don't know. If it is,
let a, b and c be the lengths of the three sides.
and let s = (a + b + c)/2
Then Area = sqrt[s*(s-a)*(s-b)*(s-c)]
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area = length by length. 3 x 3 = 9 units squared
Add together the areas of all 6 sides.
The answer will depend on the nature of the polygon and what is known about it.For a triangle, for example, there are formulae if you know 3 sides; or 2 sides and an angle; or 1 side and 2 angles. In the second case you can find the area but not the perimeter.In the case of a quadrilateral, you will require much more information, and for polygons with more sides, even more.
first find the area of one face so 3times 3= 9 in. square then 9 in times all 6 sides =54 in. square
Divide the perimeter by 3 to find the length of each of its 3 equal sides Area = 0.5*side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find its height then area is: 0.5*base*height