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You need to determine another point along the line or determine the slope of the line given the graph.

First, count the "rise" and "run" units along the graphs. To count the "rise" units, count the number of units it takes for the line to rise up. To count the "run" units, count the number of units it takes for the line to run left/right.

Remember:

- If you are running up along the line, then you are counting positive units for the "rise".
- If you are running left/right along the line, then you are counting negative/positive units for the "run".

Use this simplified form:

m = slope form = rise / run

Then, use the point-slope form to determine the equation of a line.

y - y0 = m(x - x0)

Q: How do you find equations of a line given a point and line?

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y-4=3/2(x-7)

To measure the point at which two tangents intersect each other, find an equation for each tangent line and compute the intersection. The tangent is the slope of a curve at a point. Knowing that slope and the coordinates of that point, you can determine the equation of the tangent line using one of the forms of a line such as point-slope, point-point, point-intercept, etc. Do the same for the other tangent. Solve the two equations as a system of two equations in two unknowns and you will have the point of intersection.

You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.

The shortest path is a line perpendicular to the given line that passes through the given point.

You must first write an equation for the line through the point perpendicular to the line. Then, find the intersection between the two lines. Lastly, use this point and the distance formula to find the length of the perpendicular segment connecting the given point and the original line. That will lead to the following formula, d = |AX1+BY1- C|/(sqrt(A2+B2)), Where A, B and C represent the coefficients of the given line in standard form and (X1,Y1) is the given point.

Related questions

Parallel straight line equations have the same slope but with different y intercepts

Both straight line equations will have the same slope or gradient but the y intercepts wll be different

y-4=3/2(x-7)

Points: (4, -2) Equation: 2x -y -5 = 0 Perpendicular equation: x+2y = 0 Both equations intersect at: (2 -1) Prependicular distance is the square root of (4-2)2+(-2--1)2 So the distance is the square root of 5 Knowing the equation of the line, you can work out the gradient of a line perpendicular to the line: Given the line in the form y = mx + c (where m is the gradient of the line and c is the y-intercept), the gradient of a perpendicular line (m') is given by: mm' = -1 → m' = -1/m The equation of the line perpendicular to the given line through a given point (xo, yo) can then be found by: y - yo = m'(x - xo) = -1/m(x - xo) With the two lines you can find their point of intersection, namely the point (xi, yi) that simultaneously satisfies both equations, and then use Pythagoras to find the distance from this point to the given point: distance = √((xo - xi)2 + (yo - yi)2)

is it a line that is slanted

Two points determine a line. Also there is one and only line perpendicular to given line through a given point on the line,. and There is one and only line parallel to given line through a given point not on the line.

To measure the point at which two tangents intersect each other, find an equation for each tangent line and compute the intersection. The tangent is the slope of a curve at a point. Knowing that slope and the coordinates of that point, you can determine the equation of the tangent line using one of the forms of a line such as point-slope, point-point, point-intercept, etc. Do the same for the other tangent. Solve the two equations as a system of two equations in two unknowns and you will have the point of intersection.

You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.

Finding the midpoint of a segment Drawing a perpendicular line segment from a given point to a given segment Drawing a perpendicular line segment through a given point on a given segment Drawing a line through a given point parallel to a given line

Finding the midpoint of a segment Drawing a perpendicular line segment from a given point to a given segment Drawing a perpendicular line segment through a given point on a given segment Drawing a line through a given point parallel to a given line

Finding the midpoint of a segment Drawing a perpendicular line segment from a given point to a given segment Drawing a perpendicular line segment through a given point on a given segment Drawing a line through a given point parallel to a given line