0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the next number pattern 128-134-140-146-152?
158 The pattern is t(n+1) = t(n) + 6
What number is the next logical number in the following sequence of numbers 13 17 19?
From the pattern (n + 4, n + 2, n + ?) I would say the next following number is 20 (n + 1).
Why are there more prime numbers 100 to 200 then 200 to 300?
That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".
What will the next number be in the pattern 1 3 2 3 4 6?
Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.
The square of a number minus the number is 552 find the number?
n^2 - n = 552 n^2 - n -552 = 0 (n+23)(n-24) = 0 n = 24 n can also be negative 23
What is the algebraic equation using n that can be used to find the nth term in the pattern 8163264?
A single number, such as 8163264, does not form a sequence.
How do you find the triangular number?
The nth triangular number is n(n+1)/2
How many prime numbers in intervals of 100?
There are 25 in the first 100 but there is no pattern. Furthermore, given any integer k, it is always possible to find a number n such that the k numbers after n are all non-prime. Thus, there is a number, n, such that the hundred numbers [n+1, n+100] are all composite.
What are multiples of number and how do you find them?
You find multiples of a number by multiplying that number by successive counting numbers. Let N equal the number. The first multiple is always the original number (N x 1) The rest will be N x 2, N x 3, N x 4 and so on.
What is the next number pattern 128-134-140-146-152?
158 The pattern is t(n+1) = t(n) + 6
What number is the next logical number in the following sequence of numbers 13 17 19?
From the pattern (n + 4, n + 2, n + ?) I would say the next following number is 20 (n + 1).
Why are there more prime numbers 100 to 200 then 200 to 300?
That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".
What will the next number be in the pattern 1 3 2 3 4 6?
Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.
How do you find cube?
Multiply a number by itself and then again by itself. n-cube = n*n*n
The square of a number minus the number is 552 find the number?
n^2 - n = 552 n^2 - n -552 = 0 (n+23)(n-24) = 0 n = 24 n can also be negative 23
Is there a method to find the 99th triangle number?
Oh, dude, finding the 99th triangle number is like, totally easy. You just use the formula n(n+1)/2, where n is the number of the triangle you want. So, for the 99th triangle number, you plug in 99 for n, do some quick math, and boom, you've got it!
What is the method to find the 6 triangular number?
The nth triangular number is n(n+1)/2
