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Q: How do you find number n in a pattern?
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What is the next number pattern 128-134-140-146-152?

158 The pattern is t(n+1) = t(n) + 6


What number is the next logical number in the following sequence of numbers 13 17 19?

From the pattern (n + 4, n + 2, n + ?) I would say the next following number is 20 (n + 1).


Why are there more prime numbers 100 to 200 then 200 to 300?

That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".


What will the next number be in the pattern 1 3 2 3 4 6?

Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.


The square of a number minus the number is 552 find the number?

n^2 - n = 552 n^2 - n -552 = 0 (n+23)(n-24) = 0 n = 24 n can also be negative 23

Related questions

What is the algebraic equation using n that can be used to find the nth term in the pattern 8163264?

A single number, such as 8163264, does not form a sequence.


How do you find the triangular number?

The nth triangular number is n(n+1)/2


How many prime numbers in intervals of 100?

There are 25 in the first 100 but there is no pattern. Furthermore, given any integer k, it is always possible to find a number n such that the k numbers after n are all non-prime. Thus, there is a number, n, such that the hundred numbers [n+1, n+100] are all composite.


What are multiples of number and how do you find them?

You find multiples of a number by multiplying that number by successive counting numbers. Let N equal the number. The first multiple is always the original number (N x 1) The rest will be N x 2, N x 3, N x 4 and so on.


What is the next number pattern 128-134-140-146-152?

158 The pattern is t(n+1) = t(n) + 6


What number is the next logical number in the following sequence of numbers 13 17 19?

From the pattern (n + 4, n + 2, n + ?) I would say the next following number is 20 (n + 1).


Why are there more prime numbers 100 to 200 then 200 to 300?

That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".That is because prime numbers do not follow any known pattern. However, the number of primes smaller than a number n is approximately n/ln(n) where ln is the natural logarithm.And the word for comparisons is "than" not "then".


What will the next number be in the pattern 1 3 2 3 4 6?

Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.Given ANY number it is possible to find a polynomial of order 6 such that it will predict it as the next number in the pattern. The position to value rule:Un= (2n5- 37n4+ 260n3-851n2+ 1274n + 624)/24 for n = 1, 2, 3, ... predicts 23.


How do you find cube?

Multiply a number by itself and then again by itself. n-cube = n*n*n


The square of a number minus the number is 552 find the number?

n^2 - n = 552 n^2 - n -552 = 0 (n+23)(n-24) = 0 n = 24 n can also be negative 23


What is the method to find the 6 triangular number?

The nth triangular number is n(n+1)/2


How the triangular pattern number works?

First, draw a dot. Below that, draw two dots. Then, 3 dots below it and so on. Here, you should see the pattern of the triangular number, which is the sum of consecutive integers starting at 1. The terms of that pattern are 1, 3, 6, 10, 15, ....n(1 + n)/2 where n is the total number of dots for the pattern.