For sinX you set it equal to the opposite side of the angle over the hypotenuse(SOH),cross multiply. CosX you set it equal to the adjacent side of the angle over the hypotenuse (CAH), cross multiply. Lastly for TanX set it equal to the opposite of the angle over the adjacent side of the angle and then cross multiply (TOA). I hope that's helpful :)
Sine ratio = opposite/hypotenuse
The answer depends on what ratio of the triangle you are interested in.
Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.
Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle
if the triangle has one right angle in it
Sine ratio = opposite/hypotenuse
In a right angle triangle divide the opposite by the hypotenuse to find the sine ratio.
The answer depends on what ratio of the triangle you are interested in.
if the angle of a triangle are in the ratio 7:11:18,find the angle
The Pothagerean theorem.
Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.
Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle
if the triangle has one right angle in it
Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height
Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.
If it has no right angles, it is not a right triangle and therefore you cannot name a hypotenuse of that triangle. Which implies you cannot find that side's measure.
To use the slope ratio to find a side of a triangle, you can apply the concept of the tangent of an angle in a right triangle. The slope ratio is defined as the rise (vertical change) over the run (horizontal change), which corresponds to the tangent of the angle formed by the triangle. By knowing one side and the angle, you can set up the equation: tangent(angle) = opposite/adjacent. Rearranging this equation allows you to solve for the unknown side length using the known side and angle.