For sinX you set it equal to the opposite side of the angle over the hypotenuse(SOH),cross multiply. CosX you set it equal to the adjacent side of the angle over the hypotenuse (CAH), cross multiply. Lastly for TanX set it equal to the opposite of the angle over the adjacent side of the angle and then cross multiply (TOA). I hope that's helpful :)
Sine ratio = opposite/hypotenuse
The answer depends on what ratio of the triangle you are interested in.
Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.
if the triangle has one right angle in it
Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle
Sine ratio = opposite/hypotenuse
The answer depends on what ratio of the triangle you are interested in.
In a right angle triangle divide the opposite by the hypotenuse to find the sine ratio.
if the angle of a triangle are in the ratio 7:11:18,find the angle
The Pothagerean theorem.
if the triangle has one right angle in it
Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.
Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle
Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height
Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.
If it has no right angles, it is not a right triangle and therefore you cannot name a hypotenuse of that triangle. Which implies you cannot find that side's measure.
If it has no right angles, it is not a right triangle and therefore you cannot name a hypotenuse of that triangle. Which implies you cannot find that side's measure.