if the object is a square take the square root of the area, which gives you one side length. Then multiply by 4. In this case the side length would be 15 and the perimeter would be 60.
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Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
There's not enough information here to figure that out. If it was a square, we'd know it was 15 x 15 and the perimeter would be 60. But there are four possible whole number rectangles with differing perimeters. 250 x 1, perimeter 502 75 x 3, perimeter 156 45 x 5, perimeter 100 25 x 9, perimeter 68
if the rectangle is a square 18yd x 18yd, the area = 324 sq yd. that us the largest area. As one side gets smaller, the other side get larger.If the smallest length you can measure is 1 yd., the rectangle would be 1 yd. x yd 35 yd.= 35 sq. yd. IF you can draw a line .01 yd.long, the other side of the rectangle is 36.99 yd. long. .01 yd x 36.99 yd = .3599 sq yd. There is no smallest area, only a largest area.
A "yard" is a unit of length or distance. It's not a unit of area. So "15 yd" could represent a perimeter,but it could not represent an area.I should be perimeter. Because if it was area i think it would be square yards
Perimeter is the length round the outside. A basketball court is a rectangle, so: perimeter = 2 x (length + width) = 2 x (30 yd + 40 yd) = 2 x 70 yd = 140 yd