Q: How do you find the angle between the two hands of clock?

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120 degrees is the angle made by the hands of a clock at 4 o clock. To get this answer, you could divide the clock into equal parts (12), and find the ratio of the time in terms of parts to the total number of parts of the clock (which would be 4/12 in this case). Then, you cross multiply the ratio you got, to the ratio of the unknown degrees to the total number of degrees in a circle (x/360). (4 * 360 = 12x). The answer should be 120 degrees.

The hands on a clock!

Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is: minute_deg = minute * 360 / 60 = minute * 6; The hour hand will make a complete revolution every hour, so its formula is: hour_deg = hour * 360 / 12 = hour * 30; A function to find the angle would be: int angleBetweenHands(int hour, int minute) { if(hour > 12) // In case of 24 hour clock hour -= 12; int angle = hour * 30 - minute * 6; if(angle > 180) angle = 360 - angle; return(angle); }

minute_deg = minute * 360 / 60 = minute * 6;The hour hand will make a complete revolution every hour, so its formula is:hour_deg = hour * 360 / 12 = hour * 30;A function to find the angle would be:int angleBetweenHands(int hour, int minute){if(hour > 12) // In case of 24 hour clockhour -= 12;int angle = hour * 30 - minute * 6;if(angle > 180)angle = 360 - angle;return(angle);}Read more: C_code_to_find_angle_between_hour_hand_and_minute_hand

Any angle between 0 and 180 degrees or 0 and pi radians.

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150 degrees

110 degrees.110 degrees.110 degrees.110 degrees.

If the little hand stayed on the 12, the angle would be 120°. Assuming both hands are pointing to 12 o'clock, when the big hand has moved to 20 past (1/3 of the way round) the little hand will have moved 1/3 of the way to the next number (1). So the angle between the hands will be: 1/3 × 360° - 1/3 × 1/12 × 360° = 120° - 10° = 110°.

120 degrees is the angle made by the hands of a clock at 4 o clock. To get this answer, you could divide the clock into equal parts (12), and find the ratio of the time in terms of parts to the total number of parts of the clock (which would be 4/12 in this case). Then, you cross multiply the ratio you got, to the ratio of the unknown degrees to the total number of degrees in a circle (x/360). (4 * 360 = 12x). The answer should be 120 degrees.

The hands on a clock!

The hands on a clock must be greater than 90 degrees to be obtuse, so you find times where the time is >90 degrees.Examples are: 4:00, 5:00, 6:00, 7:00, 8:00.

At the Clock Tower, hit the hands to Midnight.

Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is: minute_deg = minute * 360 / 60 = minute * 6; The hour hand will make a complete revolution every hour, so its formula is: hour_deg = hour * 360 / 12 = hour * 30; A function to find the angle would be: int angleBetweenHands(int hour, int minute) { if(hour > 12) // In case of 24 hour clock hour -= 12; int angle = hour * 30 - minute * 6; if(angle > 180) angle = 360 - angle; return(angle); }

Wheel and axle

minute_deg = minute * 360 / 60 = minute * 6;The hour hand will make a complete revolution every hour, so its formula is:hour_deg = hour * 360 / 12 = hour * 30;A function to find the angle would be:int angleBetweenHands(int hour, int minute){if(hour > 12) // In case of 24 hour clockhour -= 12;int angle = hour * 30 - minute * 6;if(angle > 180)angle = 360 - angle;return(angle);}Read more: C_code_to_find_angle_between_hour_hand_and_minute_hand

Yes, a clock can have a pendulum. Pendulum clocks use a swinging weight on a rod to regulate its timekeeping mechanism. The swing of the pendulum controls the movement of the clock's hands.

Any angle between 0 and 180 degrees or 0 and pi radians.