m + 3n = 7n = -201
7n = -201
n = -201 / 7
n = -28.71
m + 3n = -201
m + 3(-28.31) = -201
m - 86.14 = -201
m = -201 + 86.14
m = -115
So the final answer will be, m = -115 and n = -28.71
I hope this makes sense. :)
3n2 - 7n = 0 n(3n - 7) = 0 So either n = 0 or 3n-7 = 0 ie, either n = 0 or n = 7/3 = 21/3 = 2.33...
-2
x = 3 and y = 0
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Yes because if 1+0=1 than 0 plus b equals b
18 - 3n + 2 = n + 20 - 4n gather terms together on both sides of equation - 3n + 20 = - 3n + 20 0 = 0 =============no true solution here Actually, it's an infinite number, not "no solution" because it can also be done to end with n=n. I realize you didn't strictly say "no solution" but that's what it sounds like, so I'm just clarifying. -3n+20=-3n+20 -3n=-3n n=n
5n + 12 = 3n Try to get all expressions with n on the left side 5n + 12 - 3n = 3n - 3n 2n + 12 = 0 Try to get rid of 12 on the left side 2n + 12 - 12 = -12 2n = -12 n = -12/2 = -6
3n2 - 7n = 0 n(3n - 7) = 0 So either n = 0 or 3n-7 = 0 ie, either n = 0 or n = 7/3 = 21/3 = 2.33...
n(7n-3) = 0 n = 0 or n = 3/7
-2
If you mean: (2n-14)(3n+9) = 0 then it is a quadratic equation whose solution is n = -3 or n = 7
x = -½
x = 3 and y = 0
(0, 2)
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Yes because if 1+0=1 than 0 plus b equals b
A=0 b=0 c=0