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HOW to find area of parrallelogram?
Area = length*perpendicular height
What is the formula to find the area of the parrallelogram?
If a parallelogram has adjacent sides of length a and b and the angle between then is x, thenarea = a*b*sin(x).
How do you work out the area of a parrallelogram?
Multiply the height by the length of the base.a = h x b
Can you calculate the area of a parallelogram when lengths of its four sides are given?
No. The information is not sufficient to determione the area. You can "squash" the parrallelogram and so reduce its area at will.
Is a quadrilateral always a parrallelogram?
No.
HOW to find area of parrallelogram?
Area = length*perpendicular height
How t0 find the area of a parrallelogram?
If a parallelogram has adjacent sides of length a and b and the angle between then is x, thenarea = a*b*sin(x).
What is the formula to find the area of the parrallelogram?
If a parallelogram has adjacent sides of length a and b and the angle between then is x, thenarea = a*b*sin(x).
How do you find the base of a parrallelogram?
Measure the length of the "lowest" side.
Find the area of a parrallelogram with a height of 5 units and a base of 10 units?
It is: 5*10 = 50 square units
How do you work out the area of a parrallelogram?
Multiply the height by the length of the base.a = h x b
Can you calculate the area of a parallelogram when lengths of its four sides are given?
No. The information is not sufficient to determione the area. You can "squash" the parrallelogram and so reduce its area at will.
Finding the area?
to find the area of any thing you have to multiply length by width depends unless its a triangle o parrallelogram then u have to multiply base by height divided by two
What is the area of a parrallelogram if the base is 8 feet and the height is 3 ft?
24 square feet.
What is the area a parrallelogram?
If the adjacent sides are of lengths x and y units and the angle between then is t, then,Area = a*b*sin(t).
Is a parrallelogram a quadrilateral?
yes
Is a quadrilateral always a parrallelogram?
No.
