-10 is ten steps below zero.
10 is ten steps above zero.
How far do you have to climb in order to go from
10 below a place to 10 above the same place ?
140
To calculate the BTUs removed per hour, you can use the formula: BTUs = flow rate (lbs/min) × temperature change (°F) × 1. If the flow rate is 10 lbs/min and the temperature change is 15°F, the calculation is: 10 lbs/min × 15°F × 1 BTU/lb°F = 150 BTUs/min. To find the hourly rate, multiply by 60 minutes, resulting in 9,000 BTUs per hour.
A temperature change by one degree on Celsius scale equals temperature change of 1.8 degree on Fahrenheit scale or F (Fahrenheit) = 1.8 C (Celsius) + 32
To calculate the heat required to change the temperature of 28 lbs of ice from -38°F to 32°F, we need to consider both the specific heat of ice and the phase change. The specific heat of ice is about 0.5 BTU/lb°F. First, we raise the temperature of the ice from -38°F to 32°F, which is a 70°F increase. The heat required for this temperature change is approximately 28 lbs × 0.5 BTU/lb°F × 70°F = 980 BTU.
To change 1 pound of steam from 212°F to 312°F, you need to add sensible heat to increase its temperature. The specific heat of steam is approximately 1.0 BTU/lb°F. Therefore, to raise the temperature by 100°F (from 212°F to 312°F), it would require about 100 BTUs.
To find the average change in temperature per hour from 3 a.m. to 10 a.m., first calculate the total change in temperature: 22°F - (-13°F) = 35°F. The time span from 3 a.m. to 10 a.m. is 7 hours. Therefore, the average change in temperature per hour is 35°F / 7 hours = 5°F per hour.
Air pressure decreases by about 1 psi for every 10°F increase in temperature. Conversely, air pressure increases by about 1 psi for every 10°F decrease in temperature.
The change in temperature from 34°F to 67°F is an increase of 33°F.
To calculate the BTU needed to heat 10 gallons of water from 32°F to 212°F, you can use the formula: BTU = gallons × 8.34 (weight of water per gallon in pounds) × temperature change (in °F). The temperature change is 212°F - 32°F = 180°F. Thus, BTU = 10 gallons × 8.34 lbs/gallon × 180°F = 15,012 BTU.
140
To calculate the heat required to raise the temperature of 10 pounds of water from 50°F to a specific temperature, you can use the formula: [ Q = mc\Delta T ] where ( Q ) is the heat energy (in BTUs), ( m ) is the mass (in pounds), ( c ) is the specific heat capacity of water (approximately 1 BTU/lb°F), and ( \Delta T ) is the change in temperature (in °F). For example, if you want to raise it to 150°F, the temperature change (( \Delta T )) would be 100°F, so the heat required would be: [ Q = 10 , \text{lb} \times 1 , \text{BTU/lb°F} \times 100°F = 1000 , \text{BTUs} ] Adjust ( \Delta T ) based on your target temperature.
To calculate the BTUs removed per hour, you can use the formula: BTUs = flow rate (lbs/min) × temperature change (°F) × 1. If the flow rate is 10 lbs/min and the temperature change is 15°F, the calculation is: 10 lbs/min × 15°F × 1 BTU/lb°F = 150 BTUs/min. To find the hourly rate, multiply by 60 minutes, resulting in 9,000 BTUs per hour.
To determine the change in temperature between 12 noon and 4 PM, you would need to know the specific temperatures recorded at those times. If, for example, the temperature was 75°F at noon and 80°F at 4 PM, the change would be an increase of 5°F. Conversely, if the temperature dropped from 75°F to 70°F, the change would be a decrease of 5°F. Without the specific temperatures, the change cannot be accurately assessed.
Standard temperature change is 3 deg. F. per 1K ft.
10 deg F of air temp will change the press in a tire approx 1 psi
F = (1.8 * C) + 32 Example: Find Fahrenheit when Celsius = 10 F = (1.8 * 10) + 32 F = 18 + 32 F = 50 10 degrees Celsius is equal to 50 degrees Fahrenheit
The starting temperature was 11°F. Starting at 11°F, a drop of 13°F in 7 hours would result in a final temperature of -2°F.