Call the intercept with the y-axis b.
The equation for the line is then y=5x+b
With the information about the x-intercept we get:
0=5*7+b
b=-35
Slope = 0, intercept = 3
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
The slope is 1 and the y intercept is 5
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
y = mx + b <-- (Slope Intercept equation) y = 4x - 1 <-- (Slope Intercept form)
Slope = 0, intercept = 3
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
The slope is 1 and the y intercept is 5
If you mean: y = 11.2x then the slope is 11.2 and there is no y intercept
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
y = mx + b <-- (Slope Intercept equation) y = 4x - 1 <-- (Slope Intercept form)
9.5
Slope is zero y-intercept is -7 there is no x-intercept for this equation
This is the easiest form of this question, called the slope-intercept form. y = mx + b m is slope, and b is the y-intercept. The slope is 5, and the y-intercept is 2. ■
The equation is x = -7.
Solving the equation for "y" gives you the slope-intercept form.
It is 8 and the y intercept is 8