Suppose you have the expression x2 + 7x + 12. You look for two numbers that add to 7 and multiply to make 12. They are 3 and 4. You put these numbers into the factors as follows: (x+3)(x+4).
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Here is a harder example. x2 - 5x - 36. The numbers have to multiply to make -36, so one must be negative and the other positive. Since they add to -5, the big number must be negative. If you're stuck, make a list of the pairs of factors of 36: 1x36, 2x18, 3x12, 4x9, 6x6. The numbers we are looking for are 4 and -9, and the factors are (x+4)(x-9).
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These two examples are 'easy' trinomials, since they have no number in front of the x2. 'Hard' trinomials do have a number there. For example, 3x2 - 19x -14. There are several ways of doing this, but it is basically organized trial and error. The factors are (3x+2)(x-7).
Only when the discriminant of the quadratic expression is equal to or greater than zero
Leave it the way it is. (by Stephen Hawking)
Yes FOIL method can be used with quadratic expressions and equations
The first and third are quadratic expressions in x, the second is a quadratic expressions in n, and the fourth is a quadratic expressions in y. None of them are equations so cannot be solved.
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No, the quadratic equation, is mainly used in math to find solutions to quadratic expressions. It is not related to science in any way.
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
Only when the discriminant of the quadratic expression is equal to or greater than zero
Leave it the way it is. (by Stephen Hawking)
Yes FOIL method can be used with quadratic expressions and equations
Usually simple substitutions enable such expressions to be seen as quadratic expressions. The substitutions x = a2 and y = b2 give a4 + b4 - 7a2b2 = x2 - 7xy + y2 which does not have any rational factors. Consequently, the quartic in a and b does not have rational factors.
When you need to find the roots of a quadratic equation and factorisation does not work (or you cannot find the factors). The quadratic equation ALWAYS works. And when appropriate, it will give the imaginary roots which, judging by this question, you may not yet be ready for.
the difference between the two is that in quadratic u find the factors of the last term that when u add/subtract u get the answer of the middle term. while the general quadratic trinomial u find the factors of both first term and last term and proceed to trial and error. Welcome -Delin-shaw Guillermo
If the two factors of the quadratic in x are ax+band cx+d thenthe first term is acx2 and the last term is bd.
The first and third are quadratic expressions in x, the second is a quadratic expressions in n, and the fourth is a quadratic expressions in y. None of them are equations so cannot be solved.
Algebraic expressions can't be solved because they are not equations but they can be simplified.
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