It's impossible. Trigonometrical functions can be used, but only if the measure of one of the acute angles is given. If it is given, then knowing that the right angle is 90 degrees you can solve for the other acute angle. Then use sine, cosine, or tangent to relate the measure of the sides, for which a calculator is necessary.
No; the tangent ratio only deals with the lengths of the opposite side and adjacent side. You can square the two sides and add them together, then find the square root of the sum to find the length of the hypotenuse.
Yes, but it depends on what information you have about the angles.
Yes. You will need to use trigonometry. sin (angle) = opposite/hypotenuse cos (angle) = adjacent/hypotenuse tan (angle) = opposite/adjacent
By using the trigonometric ratios of Sine and Cosine. The diagonal forms the hypotenuse of a right angled triangle with the length and width of the rectangle forming the other two sides of the triangle - the adjacent and opposite sides to the angle. Then: sine = opposite/hypotenuse → opposite = hypotenuse x sine(angle) cosine = adjacent/hypotenuse → adjacent = hypotenuse x cosine(angle)
The hypotenuse only is not sufficient to determine the area of a right triangle, unless the triangle is stated to be isosceles, or there is some other information that allows determination of the length of a side in addition to the hypotenuse. The area of a right triangle with a given hypotenuse only approaches zero as one of the two acute angles approaches zero degrees.
No.
If the only information you have is the length of one side of a triangle, there are an infinite number of triangles having that length. Since the hypotenuse is defined to be "The side opposite the right angle in a plane right triangle", you will need the length of the other side to find the hypotenuse using the Pythagorean theorem. Alternatively you need to know the other angles. Then you can use the appropriate trig function to find the length of the hypotenuse.
You can't. You need some more information. If you only know the length of the hypotenuse, you can draw an infinite number of different right triangles that all have the same hypotenuse.
If it's a right angle triangle and an acute angle plus the length of a leg is given then use trigonometry to find the hypotenuse.
No; the tangent ratio only deals with the lengths of the opposite side and adjacent side. You can square the two sides and add them together, then find the square root of the sum to find the length of the hypotenuse.
In a right angles triangle the sides are named the hypotenuse (the side opposite the right angle) and the other two sides are called the adjacent and the opposite sides. 1) The sine of an angle = length of the opposite side ÷ length of the hypotenuse. 2) The cosine of an angle = length of the adjacent side ÷ length of the hypotenuse. Using 1) The length of the hypotenuse = length of the opposite side ÷ the sine of the angle. Using tables or a calculator obtain the sine of the angle and divide this into the length of the opposite side. The result will be the length of the hypotenuse.
Yes, but it depends on what information you have about the angles.
You can't. You need at least another side length or two corner angles.
Yes. If c is the length of the hypotenuse, and alpha is the angle between the hypotenuse and the base. If we say a is the length of the side opposite angle alpha and b is the length of the adjacent side, then the lengths a and b are as follows: a=h*sin(alpha) b=h*cos(alpha)
Yes. You will need to use trigonometry. sin (angle) = opposite/hypotenuse cos (angle) = adjacent/hypotenuse tan (angle) = opposite/adjacent
By using the trigonometric ratios of Sine and Cosine. The diagonal forms the hypotenuse of a right angled triangle with the length and width of the rectangle forming the other two sides of the triangle - the adjacent and opposite sides to the angle. Then: sine = opposite/hypotenuse → opposite = hypotenuse x sine(angle) cosine = adjacent/hypotenuse → adjacent = hypotenuse x cosine(angle)
Dependent on what side you are given you would use Sin(Θ) = Opposite/Hypotenuse just rearrange the formula to Hypotenuse = Opposite/Sin(Θ). Or if you are given the adjacent side use Cosine(Θ)=Adjacent/Hypotenuse, then: Hypotenuse = Adjacent/Cosine(Θ)