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To find the length of segments on a graph, you can use the distance formula, which is derived from the Pythagorean theorem. For two points ( A(x_1, y_1) ) and ( B(x_2, y_2) ), the length of the segment between them is calculated as ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Simply substitute the coordinates of the endpoints into the formula to find the length of the segment.
What else can I help you with?
How is a percentage circle graph different from a degree circle graph?
Degree graph has 360 segments , percntage has 100 segments
What is ratio of segments?
It is the length of one (or more) segments compared to the length of other segments.
What is A graph that uses a series of line segments to show changes in data?
A line graph or a bar graph.
Congruent segments are segments that have the same what?
length
What graph uses points connected by line segments to display data?
line graph
What is a graph that displays data using line segments?
The graph that displays data using line segments is a line graph.
How is a percentage circle graph different from a degree circle graph?
Degree graph has 360 segments , percntage has 100 segments
Segments that have the same length?
The answer to, "Segments that have the same length" Is Congruent Segments!
What is ratio of segments?
It is the length of one (or more) segments compared to the length of other segments.
What is graph that displays data using line segments?
A line graph.
How do you find the area of a triangle in a graph?
multiply the x-length and the y-length and 2
What is a graph that uses line segments to show how data change?
line graph
What is A graph that uses a series of line segments to show changes in data?
A line graph or a bar graph.
Congruent segments are segments that have the same what?
length
Segments of the equal lenght are what kind of segments?
Segments of equal length are congruent segments.
What graph uses points connected by line segments to display data?
line graph
A graph that uses line segments to show how data changes?
A line graph, not surprisingly!
