To find the nth term of the pattern 10, 20, 40, 70, 110, 160, first observe the differences between consecutive terms: 10, 20, 30, 40, 50. These differences increase by 10 each time, suggesting a quadratic relationship. The nth term can be expressed as a quadratic equation: ( a_n = An^2 + Bn + C ). By solving a system of equations using the first three terms, we find ( a_n = 5n^2 + 5n ).
% rate = 68.75% = 110/160 * 100% = 0.6875 * 100% = 68.75%
Expressed as a percentage, 110/160 x 100 = 68.75 percent.
The GCF is 10.
The pattern involves an increasing difference between consecutive numbers: 10 (20 - 10), 20 (40 - 20), 30 (70 - 40), and 40 (110 - 70). The differences themselves increase by 10 each time. Following this pattern, the next differences would be 50, 60, and 70, leading to the next three numbers being 160 (110 + 50), 220 (160 + 60), and 290 (220 + 70). Thus, the next three numbers are 160, 220, and 290.
70 80 80 80 90 90 100 100 110 110 120 130 160Range = 160 - 70 = 90
% rate = 68.75% = 110/160 * 100% = 0.6875 * 100% = 68.75%
The GCF is 10.
Expressed as a percentage, 110/160 x 100 = 68.75 percent.
Answer: 160
160 + 320 + 100 + 110 + 200 + 220 = 1110/6 = 185
110 pound = 49.895 160 7 kilogram
160 is exactly in the middle of 110 and 210.
The pattern involves an increasing difference between consecutive numbers: 10 (20 - 10), 20 (40 - 20), 30 (70 - 40), and 40 (110 - 70). The differences themselves increase by 10 each time. Following this pattern, the next differences would be 50, 60, and 70, leading to the next three numbers being 160 (110 + 50), 220 (160 + 60), and 290 (220 + 70). Thus, the next three numbers are 160, 220, and 290.
1 pound = 16 ounces 110 pounds = 160 ounces
70 80 80 80 90 90 100 100 110 110 120 130 160Range = 160 - 70 = 90
11/16
125