How do you find the percent ionic character?

Answer 1

Using the difference of ionic electronegativity expressed/designated as XA and XB. The formula is written as %IC={1-exp[(-0.25)(XA-XB)^2]}*100. the procedure is put in your electronegativities, (the order doesn't matter because we square the difference) and then square the difference. Then multiply that by -0.25 and put it on the exp, which you then subtract from one and times by 100. The exp is the way they write e^x for some reason.

Example: %IC of TiO2

electronegativity:

Ti=1.5

O=3.5

%IC={1-e^[(-0.25)(1.5-3.5)^2]}*100

1.5-3.5=-2

%IC={1-e^[(-0.25)(-2)^2]}*100

-2^2=4

%IC={1-e^[(-0.25)4]}*100

-0.25*4=-1

%IC={1-e^-1}*100

e^-1=0.367879441

%IC={1- 0.367879441 }*100

1- 0.367879441=0.632120559

%IC=0.632120559*100

0.632120559*100=63.2120559

Do your rounding, add a % sign and %IC of TiO2= 63%