An equation of a line requires two parameters. The slope, by itself, is not enough.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
the slope is 0
Slope or gradient = (y2-y1)/(x2-x1)
The slope is the gradient which is y2-y1/x2-x1 To find the y int you set the equation of the line equal to zero i think :/
You have to differentiate the equation. The dy/dx is the slope.
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
An equation of a line requires two parameters. The slope, by itself, is not enough.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
Use point-slope formula
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the slope is 0
Slope or gradient = (y2-y1)/(x2-x1)
You get the linear equation from a table by: Seeing the difference between the y coordinates and that should give you slope. Then find the point where x = 0 and at that point the y coordinate associated with the x is the y intercept and at the point where y = 0 the x coordinate associated is the x intercept. apply the y intercept and slope to the equation y = mx + c with m being the slope and c being the y intercept
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
The slope is the gradient which is y2-y1/x2-x1 To find the y int you set the equation of the line equal to zero i think :/