The table should give you a set of points. Take two coordinated pairs off the table and use the formula y2 - y1 divided by x2 - x1 (rise over run) to get your slope. Then take the slope and one of your points and plug it into y = mx +b with m being the slope, and b as the y-intercept.
To find the slope of a linear relationship from a table, select two points (x₁, y₁) and (x₂, y₂) from the table. The slope (m) can be calculated using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). To determine the y-intercept (b), substitute the slope and one of the points into the linear equation ( y = mx + b ) and solve for b. This will give you the equation of the line in the form ( y = mx + b ).
An equation of a line requires two parameters. The slope, by itself, is not enough.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
To determine the equation of a line from a table of values, first identify two points from the table, typically in the form (x₁, y₁) and (x₂, y₂). Calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form ( y - y₁ = m(x - x₁) ) to find the equation of the line. If necessary, rearrange it into slope-intercept form ( y = mx + b ).
Slope or gradient = (y2-y1)/(x2-x1)
You have to differentiate the equation. The dy/dx is the slope.
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
An equation of a line requires two parameters. The slope, by itself, is not enough.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
Use point-slope formula
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Slope or gradient = (y2-y1)/(x2-x1)
the slope is 0
You get the linear equation from a table by: Seeing the difference between the y coordinates and that should give you slope. Then find the point where x = 0 and at that point the y coordinate associated with the x is the y intercept and at the point where y = 0 the x coordinate associated is the x intercept. apply the y intercept and slope to the equation y = mx + c with m being the slope and c being the y intercept
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
we have to change the given equation to y=mx+b.here m is the slope