You square root both the denominator and the numerator. If the denominator can not be square rooted without an integer resulting, then multiply both the numerator and denominator by the square root in the denominator and solve from there.
Example:
√1/2...First break it down: √1 and /√2
Now take the square root of 1: 1
You now have 1/√2
Multiply the top and bottom by √2: 1√2/2
Final value using integers: 1√2/2
Example:
√4/9...First break it down: √4 and √9
Now take the square root of 4: 2
Now take the square root of 9: 3
Final value: 2/3
5 squar root 6
No, because an integer is a whole number and it's opposite (negative or positive). The square root of 80 is not a whole number.
Use the Pythagorean theorem.hypotenuse =√[52 + (√2)2] = √(25 + 2) = √27 ≈ 5.2
The square root of a/b is equal to the square root of a divided by the square root of b. I hope this helps you.
The square root of 126 is ± 11.224972.± 11.224972 expressed as a fraction is: ±2806243/250000
Assuming that squar = square rot = root pie = pi, then the answer is 1.7725, approx.
5 squar root 6
You can just take the fraction of the roots, i.e. the root of the numerator (or the upper part of the fraction) divided by the root of the denominator (the lower part).
17.4-2 is 4.17133072292 (according to my handy hpcalculator)
Yes because 5 is a rational number
find the square root of the numerator and the square root of the denominator
The square (not squar) root not rout) of pi (not pie) is approx 1.77245
No, because an integer is a whole number and it's opposite (negative or positive). The square root of 80 is not a whole number.
Use the Pythagorean theorem.hypotenuse =√[52 + (√2)2] = √(25 + 2) = √27 ≈ 5.2
well square root of 25 = 5 if you squar 5 you get an irrational number = ~2.236067977
The square root of a/b is equal to the square root of a divided by the square root of b. I hope this helps you.
Ariana Squar's birth name is Ariana L. Squar.