One way to estimate the square root of a number is by iteration. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such is the Newton-Raphson method.
If you want to find the square root of 6.5, define f(x) = x^2 – 6.5 Then finding the square root of 6.5 is equivalent to solving f(x) = 0.
Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.
Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, … [this would make more sense with suffices, but this browser is useless for mathematical notation!] Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. It works even if your first guess is not so good:
Suppose you start with x0 = 3 (a pretty poor choice since 3^2 is 9, which is not particularly near 6.5).
Even so, x3 = 2.549509766, which is accurate to 7 decimal places. Finally, remember that the negative value is also a square root.
The square root of 65 is approximately 8.06
The square root of 65 is between the integers of 8 and 9
It is: 12 times the square root of 65
It is greater because the square root of 65 is 8.06.
It is: 65
The square root of 65 is approximately 8.06
The square root of 65 cannot be simplified.
The whole number closest to the square root of 65 is 8. The whole number closest to the square root of 65 is 8.
The square root of 65 is between the integers of 8 and 9
It is: 12 times the square root of 65
It is greater because the square root of 65 is 8.06.
8.062257748
It is: 65
Just over 65 (65 squared = 4225)
-8.0623 and +8.0623 (approx).
yes
65