Since the average is the sum divided by 10 (in this case 10, because there are 10 data items), it follows that the sum is 10 times as much.
The sum of 10 plus 8 is 18.
2000 billion.
The sum of the first 10 natural numbers is 51, with an average of 5.1
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
Since the average is the sum divided by 10 (in this case 10, because there are 10 data items), it follows that the sum is 10 times as much.
If your number is 4 times ?, and the sum is 40, your problem would be 40 divided by 4. You'd get 10.
9,10,11,12
The sum of 10 plus 8 is 18.
To find 2 times the sum of y and 5, you first need to calculate the sum of y and 5 by adding y and 5 together. Once you have the sum, you then multiply it by 2 to find the final result. The expression for this calculation would be 2(y + 5).
The sum of three times a number and its square is 10 more than 6 times a number?
9x+10
The sum of the first 10 even numbers is 110.
2000 billion.
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
The sum of the first 10 natural numbers is 51, with an average of 5.1