The answer depends on the shape of the mat! The given dimension is a length so either it is the required side length and you have your answer, or it is the length of the other side not the one required. In that case, there is no way to find the answer.
As x
you can see the length of base1(example) and see the length of base2 to find out the answer of lets say the top base of a trapezoid.
A regular hexagon is a shape with 6 equal side so to find the length of one side you would take the perimeter, which is 24, and divide it by 6. 24/6 = 4. The length of 1 side is 4cm.
The length of a side is the square root of the area.
subtract the two sides that you know from the perimeter to get the unknown side.
If you know the length of one side - and the area... divide the area by the known side - to get the value of the unknown.
it can help you find the unknown length on one side of a triangle
It depends on what information about the other sides and angles you do have.
usePythagorean theorem A^2+B^2=C^2
The answer depends on the shape of the mat! The given dimension is a length so either it is the required side length and you have your answer, or it is the length of the other side not the one required. In that case, there is no way to find the answer.
P = 8s where s is the length of a side.
You begin by finding the length of the unknown side. The square of the hypotenuse is equal to the sum of the squares of the two legs. Then once you have the lengths of all 3 sides, you adum all up, and you have the perimeter.
It can be found by: hypotenuse squared minus known side squared = unknown side squared
As x
The perimeter of a shape is the distance around the outside, for instance, the length of all the sides of a square added together. The area however, is the amount of space within the shape, for example, to find the area of a square, you would simply multiply the length of the side by length of the side.
you can see the length of base1(example) and see the length of base2 to find out the answer of lets say the top base of a trapezoid.