You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
131 and 133
The whole numbers include the counting numbers, plus zero.
The sum of the whole numbers that are divisible by three and which lie between 100 and 200 is 4950.
You round to the nearest whole number.
Find two consecutive whole numbers that square root of (104) lies between.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
131 and 133
If you mean two consecutive even whole numbers then they are 140 and 142
11 and 12
9 and 10.
893 and 907
662 = 4356 4356 lies between 4355 and 4357
The whole numbers include the counting numbers, plus zero.
Factors are whole numbers that will divide into other whole numbers leaving no remainders
The answer would be 5 and 6
7 and 8