.75/x=.33
There's not enough information here to figure that out. If it was a square, we'd know it was 15 x 15 and the perimeter would be 60. But there are four possible whole number rectangles with differing perimeters. 250 x 1, perimeter 502 75 x 3, perimeter 156 45 x 5, perimeter 100 25 x 9, perimeter 68
27 is 75% of: Let x = value you are looking for 27 = 75/100 x 27 = 0.75 x 27/.75 = x 36 = x or x = 36 36 is the answer. Check: 36 * 75% = 27 so answer checks out.
Since the perimeter is already known and there are no additional values of sides, nor is the shape known, one would mathematically say the x = 24 cm.
Area = side x side; perimeter = side x 4.
x=7 ft.
A+ =7
You cannot solve this equation without knowing the shape.
That question can't be answered without seeing the drawing. We need to know the shape of the figure, what part of it is labeled 'x', and any numbers that are given.
.75/x=.33
(70 + 75) x 2
There's not enough information here to figure that out. If it was a square, we'd know it was 15 x 15 and the perimeter would be 60. But there are four possible whole number rectangles with differing perimeters. 250 x 1, perimeter 502 75 x 3, perimeter 156 45 x 5, perimeter 100 25 x 9, perimeter 68
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
p = 75+75+45+45=240cm a = 75 x 45 = 3375cm
27 is 75% of: Let x = value you are looking for 27 = 75/100 x 27 = 0.75 x 27/.75 = x 36 = x or x = 36 36 is the answer. Check: 36 * 75% = 27 so answer checks out.
If your shape is a rectangle then your y=30cm
Since the perimeter is already known and there are no additional values of sides, nor is the shape known, one would mathematically say the x = 24 cm.