To calculate the standard error for a proportion, you can use the formula: [ SE = \sqrt{\frac{p(1 - p)}{n}} ] where (p) is the sample proportion and (n) is the sample size. If the proportion is not given in your question, you'll need to specify a value for (p) to compute the standard error. For a sample size of 25, substitute that value into the formula along with the specific proportion to find the standard error.
To determine the value of x that makes the proportion true, you need to set up the equation based on the given proportion. For example, if the proportion is a/b = c/d, you can cross-multiply to get ad = bc. Then, solve for x by isolating it on one side of the equation. If you provide the specific proportion, I can help you find the value of x.
for a normal-shaped distribution with n=50 and siqma =8 : a- what proportion of the scores have values between 46 and 54? b- for samples of n= 4, what means have values what proportion of the sample mean have values between 46 and 54? c- for samples of n= 16, what means have values what proportion of the sample mean have values between 46 and 54?
i did the n-telopeptide test
3n+8=a To find the value of n, you need to know the value of a.
To calculate the standard error for a proportion, you can use the formula: [ SE = \sqrt{\frac{p(1 - p)}{n}} ] where (p) is the sample proportion and (n) is the sample size. If the proportion is not given in your question, you'll need to specify a value for (p) to compute the standard error. For a sample size of 25, substitute that value into the formula along with the specific proportion to find the standard error.
To determine the value of x that makes the proportion true, you need to set up the equation based on the given proportion. For example, if the proportion is a/b = c/d, you can cross-multiply to get ad = bc. Then, solve for x by isolating it on one side of the equation. If you provide the specific proportion, I can help you find the value of x.
for a normal-shaped distribution with n=50 and siqma =8 : a- what proportion of the scores have values between 46 and 54? b- for samples of n= 4, what means have values what proportion of the sample mean have values between 46 and 54? c- for samples of n= 16, what means have values what proportion of the sample mean have values between 46 and 54?
2/7 = n/14
i did the n-telopeptide test
3n+8=a To find the value of n, you need to know the value of a.
3
The answer will depend on where n appears in the fraction.
Direct Proportion-As one of the value increases,so does the other. Indirect Proportion-As one value increases,the other decreases. ~Hannah^^
To find the proportion of N in Ca3N2, we calculate the total atomic mass of N in the compound which is 2 * 14 = 28 (since there are 2 nitrogen atoms in Ca3N2). The total atomic mass of Ca3N2 is 3 * 40 + 2 * 14 = 136. Therefore, the proportion of N in Ca3N2 by mass is 28/136 = 0.206 (or 20.6%).
It is the value which represents the proportion as a part of 100.
n(16) + 37 = 53