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Cool question !

Answer - half it then cube it

to prove it - an example for you

if cube diagonal (not square diagonal) is 100,

then using pythagoras theorm the square diagonal = 70.71068,

If square the square diagonal = 70.71068,

then using pythagoras theorm the side length = 50

therefore the volume = 50 ^ 3 = 25000 units

works with any numbers

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Q: How do you find the volume of a cubical box when diagonal is given?

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If the diagonal is d thenV = [d/sqrt(3)]^3

You cannot. There is not enough information.

width = volume/(length*height)

The answer depends on what information you are given: (volume, breadth and height), (surface are, breadth and height), (principle diagonal, breadth and height), (mass, density, breadth and height) or some other set.

Divide the rectangle in two triangles and then use the pythagorean theorem to find the remaining sides.

Related questions

The volume of an oblong is: volume = length x width x height As the box is cubical, ie is a cube, all sides are of equal length, thus: volume_cube = side x side x side = side3 So, given the volume: side = cube_root(volume) ie, take the cube root of the volume of 2.197cm3.

you don't. you have your teacher do that for you

If the diagonal is d thenV = [d/sqrt(3)]^3

The length of each edge is: 1.5 meters.

You cannot. There is not enough information.

The answer depends on what information is provided: the volume, total surface area, principal diagonal, minor diagonal, etc.

The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.

Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.

volume = volume x density

Volume = pi*r2*h

Multiply them: density*volume = mass

By comparing the volume given to each figure.

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