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  1. Take a large enough clear rectangular tank and pour in a volume of water that is large enough to take the stopper.
  2. Mark on the tank the top of the water.
  3. Drop the stopper into the water.
  4. Find the increase in volume of the water by finding the increase in height of the water
  5. volume = cross-sectional_area_of_tank x

    increase_in_height_of_water

Example.


Suppose the tank is 10cm (wide) by 15 cm (long) by 30cm (high).

Pour water in it and it comes to about 20 cm (exact height does not matter) and this is marked on the tank.

The stopper is dropped in and the new top of the water is 1.2 cm above the mark (of the previous stop of the water).


volume stopper = cross-sectional_area x increase_in_water_level

= (10 cm x 15 cm) x 1.2 cm

= 180 cm3


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Q: How do you find the volume of an irregular glass stopper?
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