1, 1, 2, 3, 5, 8
How do i find the mode of the number six?
Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.However, the only solution based on a polynomial of order 5 isUn = (11n5 - 195n4 + 1305n3 - 4065n2 + 5704n - 2340)/60 for n = 1, 2, 3, ...and according to this rule, the next (missing) number is 45.
3.3.5.4.4.6 It seems that the sequence takes the doubled numbers than adds two to the said number, such as five. So with that theory it would be logical that six would come after the doubled fours.
Lacking any unmentioned specific limitations in the rather vague question; Yes, eventually. Even in a 'random' string of numbers, any six consecutive numbers will eventually occur again, assuming the string of numbers is sufficiently long (such as in the digits of pi). Another example: Six dice, each one with its 6 surfaces numbered 1 to 6, when thrown will give six numbers facing upwards. That same combination (or sequence) of six numbers will eventually appear again if the 6 dice are thrown a sufficient number of times.
This question cannot be answered for two main reasons. The first is that you have not specified where, in the sequence, the missing number is meant to be. Clearly that makes a difference.Suppose you assume the missing number is the last in the sequence, then any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one. The same applies, wherever in the sequence the missing number was meant to be.
2 and then, after the decimal point, a sequence of 0s.
1, 1, 2, 3, 5, 8
How do i find the mode of the number six?
Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.However, the only solution based on a polynomial of order 5 isUn = (11n5 - 195n4 + 1305n3 - 4065n2 + 5704n - 2340)/60 for n = 1, 2, 3, ...and according to this rule, the next (missing) number is 45.
The numbers in the sequence 854917610320 are arranged in alphabetical order thus: eight, five, four, nine, one, seven, six, ten, three, twenty.
3.3.5.4.4.6 It seems that the sequence takes the doubled numbers than adds two to the said number, such as five. So with that theory it would be logical that six would come after the doubled fours.
Lacking any unmentioned specific limitations in the rather vague question; Yes, eventually. Even in a 'random' string of numbers, any six consecutive numbers will eventually occur again, assuming the string of numbers is sufficiently long (such as in the digits of pi). Another example: Six dice, each one with its 6 surfaces numbered 1 to 6, when thrown will give six numbers facing upwards. That same combination (or sequence) of six numbers will eventually appear again if the 6 dice are thrown a sufficient number of times.
2 million in numbers is 2,000,000. Since a million has six zeros, you simply have to add six zeros after your number (2) to find your answer.
The numbers are 11, 12, 13, 14, 15 and 16.
It appears the sequence is of numbers in descending order followied by the number 8: 9(8)8(8)7(8)6(?), therefore, if the sequence is true, the number six should be followed by the number 8.
The six digit receipt numbers for Dunkin Donuts differ by location. These numbers are not listed publicly and can only be obtained with your customer receipt.