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What are the first six numbers in the Fibonacci sequence?
1, 1, 2, 3, 5, 8
How do you find three numbers with a mode of 6?
How do i find the mode of the number six?
What is the missing number in the sequence 7 8 5 5 3 4?
Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.However, the only solution based on a polynomial of order 5 isUn = (11n5 - 195n4 + 1305n3 - 4065n2 + 5704n - 2340)/60 for n = 1, 2, 3, ...and according to this rule, the next (missing) number is 45.
What is the next number in the sequence 3.3.5.4.4?
3.3.5.4.4.6 It seems that the sequence takes the doubled numbers than adds two to the said number, such as five. So with that theory it would be logical that six would come after the doubled fours.
Did the same six numbers ever come out twice?
Lacking any unmentioned specific limitations in the rather vague question; Yes, eventually. Even in a 'random' string of numbers, any six consecutive numbers will eventually occur again, assuming the string of numbers is sufficiently long (such as in the digits of pi). Another example: Six dice, each one with its 6 surfaces numbered 1 to 6, when thrown will give six numbers facing upwards. That same combination (or sequence) of six numbers will eventually appear again if the 6 dice are thrown a sufficient number of times.
