How do you find two numbers one is double the other and the sum is 1407?

Answer 1

let the smaller number be n; then the larger number is 2n,

and their sum is n + 2n = 3n = 1407

→ dividing 1407 by 3 will give the smaller number: n = 1407 ÷ 3 = 469

→ multiplying this by 2 gives the larger number: 2n = 2 x 469 = 938