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2 x 6000 = 12000
one-tenth of one-fourth of one fifth of one-half of 12000 = 30 1/10 * 1/4 * 1/5 * 1/2 * 12000 = 12000/400 = 30
1/10 x 1/4 x 1/5 x 1/2 x 12000 = 1/400 x 12000= 30
11997 One calculation. 12000 is 9 x 1333.33 recurring. The largest number as a multiple of 9 which is less than 12000 would be that number which is one decimal place lower than the above number. That is 1333.333.......n2. There would be an infinite number of decimal places before the 2 I leave the calculation as an exercise to the student
Since it's compound interest..End of year 1 = 12000 + 1200 = 13200End of year 2 = 13200 + 1320 = 14520End of year 3 = 14520 + 1452 = 15972