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(4+2)x3+1=19

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Q: How do you get 19 using 1 2 3 4 once?
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Related questions

How do you get 19 by only using 1234 once?

4(2+3)-1=19


How do you get to 38 using only 1 2 3 4 once?

2*(4! - 3! + 1) = 2*(24 - 6 + 1) = 2 * 19 = 38


How do you get 19 by using 1 2 3 4?

It is by: 3*(4+2)+1 = 19


Write a number sentence using 19 3 2 8 only once to equal 5?

19 -(3 x 2) - 8 = 19 - 6 - 8 = 5


What is the prime factorization of 171 using exponents?

171 = 3^2*19.


What equals 76 using 6 numbers?

1, 2, 4, 19, 38, 76: 1 x 76, 2 x 38, 4 x 19.


What is the prime factorization of 114 using exponents?

2^1 x 3^1 x 19^1


How do you equal 19 using 1 5 2 3?

If combining digits to form 2-digit numbers is allowed then some solutions are :- 21 + 3 - 5 = 19 23 + 1 - 5 = 19


How do get 22 only using these numbers once 1 2 3 4?

2*(4*3 - 1)


What are the factors and prime factors of 38?

38 is a composite number; it has factors other than 1 and itself. It is not a prime number.The 4 factors of 38 are 1, 2, 19, and 38.The factor pairs of 38 are 1 x 38 and 2 x 19.The proper factors of 38 are 1, 2, and 19 or,if the definition you are using excludes 1, they are 2 and 19.The prime factors of 38 are 2 and 19.The 2 distinct prime factors (listing each prime factor only once) of 38 are 2 and 19.The prime factorization of 38 is 2 x 19.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.


What is the enrichment of 16 only using 1 2 3 and 4?

only using the numbers once


What is 19.5 as an improper fraction?

19/5 = 19 1/2 19 1/2 = [(19 x 2) + 1] / 2 => [38+1] /2 39/2