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What is the prime factorization of 171 using exponents?
171 = 3^2*19.
What is the prime factorization of 114 using exponents?
2^1 x 3^1 x 19^1
How do you equal 19 using 1 5 2 3?
If combining digits to form 2-digit numbers is allowed then some solutions are :- 21 + 3 - 5 = 19 23 + 1 - 5 = 19
What is the enrichment of 16 only using 1 2 3 and 4?
only using the numbers once
How do get 16 only using these numbers once 1 2 3 4?
3-1=2 then 2x2x4=16.
How do you get 19 by only using 1234 once?
4(2+3)-1=19
How do you get to 38 using only 1 2 3 4 once?
2*(4! - 3! + 1) = 2*(24 - 6 + 1) = 2 * 19 = 38
How do you get 19 by using 1 2 3 4?
It is by: 3*(4+2)+1 = 19
Write a number sentence using 19 3 2 8 only once to equal 5?
19 -(3 x 2) - 8 = 19 - 6 - 8 = 5
What is the prime factorization of 171 using exponents?
171 = 3^2*19.
What equals 76 using 6 numbers?
1, 2, 4, 19, 38, 76: 1 x 76, 2 x 38, 4 x 19.
What is the prime factorization of 114 using exponents?
2^1 x 3^1 x 19^1
How do you equal 19 using 1 5 2 3?
If combining digits to form 2-digit numbers is allowed then some solutions are :- 21 + 3 - 5 = 19 23 + 1 - 5 = 19
How do get 22 only using these numbers once 1 2 3 4?
2*(4*3 - 1)
What is the enrichment of 16 only using 1 2 3 and 4?
only using the numbers once
What are the factors and prime factors of 38?
38 is a composite number; it has factors other than 1 and itself. It is not a prime number.The 4 factors of 38 are 1, 2, 19, and 38.The factor pairs of 38 are 1 x 38 and 2 x 19.The proper factors of 38 are 1, 2, and 19 or,if the definition you are using excludes 1, they are 2 and 19.The prime factors of 38 are 2 and 19.The 2 distinct prime factors (listing each prime factor only once) of 38 are 2 and 19.The prime factorization of 38 is 2 x 19.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.
How do get 16 only using these numbers once 1 2 3 4?
3-1=2 then 2x2x4=16.
