(4+2)x3+1=19
171 = 3^2*19.
2^1 x 3^1 x 19^1
If combining digits to form 2-digit numbers is allowed then some solutions are :- 21 + 3 - 5 = 19 23 + 1 - 5 = 19
only using the numbers once
1 x 2 sqrt(4) = 4
4(2+3)-1=19
2*(4! - 3! + 1) = 2*(24 - 6 + 1) = 2 * 19 = 38
It is by: 3*(4+2)+1 = 19
19 -(3 x 2) - 8 = 19 - 6 - 8 = 5
171 = 3^2*19.
2*(4*3 - 1)
1, 2, 4, 19, 38, 76: 1 x 76, 2 x 38, 4 x 19.
2^1 x 3^1 x 19^1
If combining digits to form 2-digit numbers is allowed then some solutions are :- 21 + 3 - 5 = 19 23 + 1 - 5 = 19
only using the numbers once
1 x 2 sqrt(4) = 4
3-1=2 then 2x2x4=16.