(4.4+4)/0.4
21/4 = 5.25
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
Assuming that you are only using current US coins (5, 10, 25 and 50 cents), the answer is 21. NickelsDimesQuartersHalves1500013100112009300740055003600170010010811062104310241005105020312012205001310112010011
It can be: (5*6)-21 = 28
(4.4+4)/0.4
21/4 = 5.25
4$4=*^5 then ..... from the 5 you do @ 4 ...... finally 4 * 2 making it 21
It has only four factors and they are: 1, 3, 7 and 21
21
There are only two common factors for 56 and 21. They are 1 and 7.
4! - 4 + 4/4
21^4
2+3=5... 5x4=20... 20+1=21 !
The number 21 has only four factors: 1, 3, 7, and 21. Many number have more than four factors. Among them are 1x2x3x4x5 = 120.
If 21 is a factor of a number, then the factors of 21 must also be factors. So 3 and 7
63 and 21 42 and 42 three twenty-eights four twenty-ones six fourteens seven twelves twelve sevens fourteen sixes twenty-one fours twenty-eight threes forty-two twos eighty-four ones