2 * 3 - 7 + 8, although you don't require BIDMAS for that!
By using: (3*6)+(3*2) = 24
8 divided by 3 = 2 and 2/3
7 × 3 + 6 ÷ 2
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
Using 1, 2, and 3, you can make 27 whole numbers.
2x3-10 is -4, as (using BIDMAS), we firstly multiply 2 by 3 (6) and finally subtract the 10, leaving us with -4.
By using: (3*6)+(3*2) = 24
21+3 or using all the numbers: 21 + (3*(2-1))
8 divided by 3 = 2 and 2/3
(5 - 3)/2
7 × 3 + 6 ÷ 2
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
Using 1, 2, and 3, you can make 27 whole numbers.
(9-(2*3))8
5+4-3+2
9+3+(-2*-6) = 24