This was taught to me in 1952:
"The sum of the interior angles of an n-sided polygon is (2n - 4) right angles"
So double the number of sides, subtract 4 and multiply your answer by 90o
Maybe an easier one to remember: (n - 2) x 180°.
Here's why it might be easier: Note that a triangle has 180°. A polygon must have at least 3 sides (triangle): hence n - 2 is the smallest one you can have. If n = 2 then (n-2 = 0) so you have 0° (not a polygon). With n=3, (n-2 = 1), so you have 180°.
And so on.
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The exterior angles always, in any shape, add up to 360. The interior angles sum depends on the number of sides.
1980 degrees
900 degrees
If it's a quadrilaterl shape then the 4 interior angles will add up to 360 degrees in compliance with the formula: (number of sides-2)*180 = sum of interior angles
20 sides