Q: How do you get the volume if 0.9m and 1.0 m?

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The volume of any prism is: volume = area_of_base x height which can be rearranged to give: area_of_base = volume ÷ height Thus: area_of_base = 320 m3 ÷ 10 m = 32 m2

V = 523.6 m3

volume = width x length x height (for a rectangular object) = 5 m x 7 m x 10 m = 350 m3

m = mass rho = density V = volume rho = m/V m = rho * V = (15 g/cm^3) * (10 cm^3) = 150 g

Both atom and its nucleus are considered to be spherical. Hence using the formula 4/3 pi r3 we can find the volume. In case of atom r would be of the order of 10-11 m and that for nucleus it is of the order of 10-15 m

Related questions

Volume of cube: 10*10*10 = 1000 cubic m

The volume of any prism is: volume = area_of_base x height which can be rearranged to give: area_of_base = volume ÷ height Thus: area_of_base = 320 m3 ÷ 10 m = 32 m2

dormant

The volume of a rectangular solid is given by V = length x width x height. In this case, the length is 7.08 x 10^3 m, the width is 2.18 x 10^2 m, and the height is 4.51 x 10^3 m. Therefore, the volume of the iron piece is 7.08 x 10^3 m x 2.18 x 10^2 m x 4.51 x 10^3 m = 7.70 x 10^10 cubic meters.

The volume of the salt crystal is calculated by multiplying the three dimensions together: V = (2.44 x 10^-2 m) * (1.4 x 10^-3 m) * (8.4 x 10^-3 m) = 2.85 x 10^-7 m^3.

V = 523.6 m3

2.87x10-7 m3

volume = width x length x height (for a rectangular object) = 5 m x 7 m x 10 m = 350 m3

m = mass rho = density V = volume rho = m/V m = rho * V = (15 g/cm^3) * (10 cm^3) = 150 g

Using the formula Density = Mass / Volume and rearranging for Volume, we find Volume = Mass / Density. Plugging in the values, we get Volume = (3.302 x 10^23 kg) / (5.43 x 10^3 kg m^-3) = 6.08 x 10^19 m^3. Therefore, the volume of Mercury is 6.08 x 10^19 cubic meters.

What is the volume of an m and m

2.9 x 10-7 m -3