First, you look at the equation long enough to recognize that it's the equation
of a straight line with [ slope = 1 ] and [ y-intercept = 0 ].
Then you draw that line. It passes through the origin, and slopes up toward the
right at 45 degrees.
As another technique, you could use the equation to calculate two points on the line,
then mark the points on the graph, and draw a line between them.
To calculate two points, choose two values for 'x', and then calculate the value
of 'y' for each one.
Let's just pick two numbers out of the blue for 'x':
x = 2 and x = 9 .
Can you use the equation [ y = x ] to calculate the value of 'y' that goes with each one ?
That's right. Good work. When x=2, 'y' is also 2. And when x=9, 'y' is also 9.
So now you have two points on the graph ... (2, 2) and (9, 9).
Using a soft pencil, mark each of those two points on your graph with a small dot.
Then, using the same pencil along with a ruler, draw a line that connects the two
dots. You can extend the line as far as you want to, past either point, in either direction.
The graph shifts downward (negative y) by 9 units.
You subtract X from both sides, in which u get y=x-4; u should be able to graph that
The equation is y=x(x+1)(x-2)2
y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].
y = x + 3The graph of that equation is a straight line with a slope of 1 (45° rising to the right)and passing through the point y=3 on the y-axis.
The graph shifts downward (negative y) by 9 units.
y=x-2
It is y = x + 4
You subtract X from both sides, in which u get y=x-4; u should be able to graph that
The diagonal line collapses into a single point on that line.
The equation has no slope. The graph of the equation is a straight line with a slope of -1 .
The equation is y=x(x+1)(x-2)2
answer is 1
y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].
y = x + 3The graph of that equation is a straight line with a slope of 1 (45° rising to the right)and passing through the point y=3 on the y-axis.
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
The line y = x will shift up when you add a value to x and shift down when you subtract a value from x.