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The graph of y = x - 8 is a straight line. The slope of the line is 1, and it intersects the y-axis at the point y = -8.
When you plug in x = 0, you get y = 8. When you plug in x = 8, you get y = 0. So the graph of y = x - 8 (which is clearly linear, a straight line, because it only has x to the first power) is the graph of the straight line that goes through the points (0,8) and (8,0).
To graph the equation (y = 8), draw a horizontal line across the y-axis at the point where (y = 8). This line will extend infinitely in both the positive and negative x-directions. The graph represents all points where the value of (y) remains constant at 8, regardless of the value of (x). Make sure to label the line appropriately on your graph.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
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The graph of y = x - 8 is a straight line. The slope of the line is 1, and it intersects the y-axis at the point y = -8.
When you plug in x = 0, you get y = 8. When you plug in x = 8, you get y = 0. So the graph of y = x - 8 (which is clearly linear, a straight line, because it only has x to the first power) is the graph of the straight line that goes through the points (0,8) and (8,0).
To graph them, you need to put them into the formula y=mx+b. If x+y=8 subtract x to get y=-x+8. 8 is the y-intercept and your line should be heading downward from left to right.
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
The graph of [ x=8 ] is a vertical line through the point 8 on the x-axis. It never touches the y-axis, and has no y-intercept.
To graph the equation (y = 8), draw a horizontal line across the y-axis at the point where (y = 8). This line will extend infinitely in both the positive and negative x-directions. The graph represents all points where the value of (y) remains constant at 8, regardless of the value of (x). Make sure to label the line appropriately on your graph.
The first thing to not is that the only powers of x and y in the equation are one. That means the graph is a straight line. Any two points on a straight line determine the whole of the straight line. So solve the equation for x = 0 and for y = 0. Thus, when x = 0, the equation becomes y = 8 - 0 ie y = 8 so (0, 8) is a point on the graph. and when y = 0, the equation becomes 0 = 8 - x ie x = 8 so (8, 0) is another point on the graph. Join up these two points and extend the line further in both directions.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
y=(1/4)x represents a slope-intercept equation. You graph it by inserting a value for x, like 8, and then solving the equation to see what y equals. In this instance, you can see that if x=8, then y=(1/4)*(8) and therefore, y=2. So, you graph x=8 and y=2 for a single point. To get a second point, insert another x value, like 4, and that will lead to another y value; 1. The 2 points here are (8,2) and (4,1); to get the line, simply draw a line that goes through both the points.
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