y = 5x + 3
To graph this line, we need to find two points of it on a graph and draw a straight edge using them. Two easy-to-find points are the y- and x-intercepts. The y-intercept of any linear function in the form
y = mx + b
is simply b. Is this case, b = 3. So a point must be (0,3). For the x-intercept, set y = 0 and solve for x:
0 = 5x + 3
-3 = 5x
-3/5 = x.
So a second point (-3/5,0).
5x plus 3 does equal 3 plus 5x; commutative law.
5x+3 = 3x+11 5x-3x = 11-3 2x = 8 x = 4
-4x + 3 = -5x + 3add 5x to each sidex + 3 = 3subtract three from each sidex = 0
3 + 5x = 38 -> 5x = 35 -> x = 7
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
5x plus 3 does equal 3 plus 5x; commutative law.
33
5x+3 = -17 5x = -17-3 5x = -20 x = -4
5x + 3 = -12 5x =-12-3 =-15 x = -3
5x - 4x = 13 - 3 ie x = 10
5x+3 = 3x+11 5x-3x = 11-3 2x = 8 x = 4
-4x + 3 = -5x + 3add 5x to each sidex + 3 = 3subtract three from each sidex = 0
3 + 5x = 38 -> 5x = 35 -> x = 7
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
Multiply the bottom equation by -1
Yes.
5x+18 = 2x+9 5x-2x = 9-18 3x = -9 x = -3 and y = 3