You need to know the domain over which you are required to graph the function.
Suppose it is between 0 and 10.
Choose x = 0 and substitute this value into the equation y = 6x + 5. It becomes
y = 6*0 + 5 = 0 + 5 = 5. So mark the point (0, 5) on the grid.
Choose x = 10 and substitute this value into the equation y = 6x + 5. It becomesy = 6*10 + 5 = 60 + 5 = 65. So mark the point (10, 65) on the grid.
You can join these two points with a straight line and you are done. However, it is safer to do a third point, say x = 5.The equation then gives y = 6*5 + 5 = 30 + 5 and so mark the point (5, 35).
If the 3 points are in the same straight line (they are collinear) you are home. If not, you have made a mistake in one of your calculations.
y=(6x-5)/3
6x+5=3x+5 5=9x+5 x=0
6
6x+7 = -56x = -12x = -2
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
6x + 3 = 2x + 5 4x = 2 x=1/2
3x + 5 = 6x + 23 -3x = 18 x = -6
x=5
10
6x-4+7=-5 6x+3=-5 6x=-8 x=-8/6 = -4/3
x+5=6x=1
6x - 8 + 2x - 5 = 7 - 2x ?