answersLogoWhite

0


Best Answer

There is no easy way.

You need to prove that for any pair of points A and B in the set S, the point C = A + mB is in S for 0 ≤ m ≤ 1.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you identify convex sets easily?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Is the union of two convex sets a non-convex set?

the union of two convex sets need not be a convex set.


What is the difference between well-defined and not well- defined sets?

well-defined sets are sets that can identify easily while not well-defined are those that cannot determined easily :)


What has the author Steven R Lay written?

Steven R. Lay has written: 'Convex sets and their applications' -- subject(s): Convex sets


How can you identify a concave mirror and a convex mirror in a stainless steel spoon?

look at it


Why is it important to be able to identify sets and set theory as related to business operations?

Why is it important to be able to identify sets and set theory as related to business operations?


What is non-convex and convex?

These terms describe polygons. To identify a polygon as convex, we draw a segment from any vertex to any other vertex. This segment cannot go outside of the polygon. Non-convex is concave. If we draw a segment from a vertex to any other vertex, at least one of the segments will go outside of the polygon.


Is Feasible region is necessary to be a convex set?

Yes, in optimization problems, the feasible region must be a convex set to ensure that the objective function has a unique optimal solution. This is because convex sets have certain properties that guarantee the existence of a single optimum within the feasible region.


Intersection of two convex set is convex?

The proof of this theorem is by contradiction. Suppose for convex sets S and T there are elements a and b such that a and b both belong to S∩T, i.e., a belongs to S and T and b belongs to S and T and there is a point c on the straight line between a and b that does not belong to S∩T. This would mean that c does not belong to one of the sets S or T or both. For whichever set c does not belong to this is a contradiction of that set's convexity, contrary to assumption. Thus no such c and a and b can exist and hence S∩T is convex.


Is a ploygon convex or not convex?

a polygon is convex


Where can you sell proof sets proof sets?

You can bring them to a coin dealer but you will get more selling them on EBay. Most sets are not very valuable. you can easily Google the year and get the value.


Why do cars have regisration plates?

So that police can identify them easily.


Why do greyhounds wear jackets for a race?

To easily identify which dog is which.