I assume you mean ex ? If so, by definition:
∫ex dx = ex + C
Most calculus textbooks have a table of integrals which will list the integrals of other common forms of exponential & logarithmic functions.
2x
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
The integral of e-2x is -1/2*e-2x + c but I am not sure what "for x0" in the question means.
= inegrate (e-2x) / derivate -2x = (e-2x)/-2-> integral esomething = esomething , that's why (e-2x) don't change-> (-2x)' = -2
You integrate each element of the matrix.
-ion. Drop the e, and integrate becomes integration.
2x
e 2x = (1/2) e 2x + C ============
e^x/1-e^x
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
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The integral of e-2x is -1/2*e-2x + c but I am not sure what "for x0" in the question means.
= inegrate (e-2x) / derivate -2x = (e-2x)/-2-> integral esomething = esomething , that's why (e-2x) don't change-> (-2x)' = -2
This person just asked me to integrate the word integrate into a sentence.
How Management of Technology Innovation integrated with business strategy
You integrate each element of the matrix.
{xe^x dx integrate by parts let f(x) = x so f'(x) = 1 and g(x) = e^x so g'(x) = e^x so.. f(x)*g(x) - {(g(x)*f'(x)) dx therefore xe^x - {(e^x * 1) dx so.. xe^x - e^x + C factorize so... (x-1)e^x + C