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u simply click log in, type ur username and pass, pick a server and log on

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Q: How do you log on to pr2?
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Continue Learning about Math & Arithmetic

What is the formula liquid volume in cylinder?

Volume = 1/3 pr2 x height V= 1/3 pr2h Surface = pr2 + prs S = pr2 + prs =pr2 + pr


Finding the perimeter of an object?

It depends what geometric shape the object is.ShapesFormulaRectangle:Area = Length X WidthA = lwPerimeter = 2 X Lengths + 2 X WidthsP = 2l + 2wParallelogramArea = Base X Heighta = bhTriangleArea = 1/2 of the base X the heighta = 1/2 bhPerimeter = a + b + c(add the length of the three sides)TrapezoidPerimeter = area + b1 + b2 + cP = a + b1 + b2 + cCircle Try the Online tool.The distance around the circle is a circumference. The distance across the circle is the diameter (d). The radius (r) is the distance from the center to a point on the circle. (Pi = 3.14) More aboutcircles.d = 2rc = pd = 2 prA = pr2(p=3.14)Rectangular SolidVolume = Length X Width X HeightV = lwhSurface = 2lw + 2lh + 2whPrismsVolume = Base X Heightv=bhSurface = 2b + Ph (b is the area of the base P is the perimeter of the base)CylinderVolume = pr2 x heightV = pr2 hSurface = 2p radius x heightS = 2prh + 2pr2PyramidV = 1/3 bhb is the area of the baseSurface Area: Add the area of the base to the sum of the areas of all of the triangular faces. The areas of the triangular faces will have different formulas for different shaped bases.ConesVolume = 1/3 pr2 x heightV= 1/3 pr2hSurface = pr2 + prsS = pr2 + prs=pr2 + prSphereVolume = 4/3 pr3V = 4/3 pr3Surface = 4pr2S = 4pr2


Log 2 plus log 4 equals log 2x?

log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4


how do i log in?

how do i log in


What is log base 5of 125?

log(5)125 = log(5) 5^(3) = 3log(5) 5 = 3 (1) = 3 Remember for any log base if the coefficient is the same as the base then the answer is '1' Hence log(10)10 = 1 log(a) a = 1 et.seq., You can convert the log base '5' , to log base '10' for ease of the calculator. Log(5)125 = log(10)125/log(10)5 Hence log(5)125 = log(10) 5^(3) / log(10)5 => log(5)125 = 3log(10)5 / log(10)5 Cancel down by 'log(10)5'. Hence log(5)125 = 3 NB one of the factors of 'log' is log(a) a^(n) The index number of 'n' can be moved to be a coefficient of the 'log'. Hence log(a) a^(n) = n*log(a)a Hope that helps!!!!!